Position f(t) = 2t² on [0, 3]
- f(0) = 0 and f(3) = 18
- (f(3) − f(0)) / (3 − 0) = (18 − 0) / 3
- average velocity = 6 ft/s
This is the slope of the secant line through (0, 0) and (3, 18).
Connect familiar slope to average and instantaneous rates of change, then use shrinking time intervals to estimate a tangent slope.
01 · Watch
Video not loading? Watch directly on YouTube.
02 · Understand
03 · Vocabulary
Keep the geometry, the meaning, and the units connected.
04 · Apply
Each quotient is a secant slope until the interval shrinks to an instant.
This is the slope of the secant line through (0, 0) and (3, 18).
| Interval | Average velocity |
|---|---|
| [2, 3] | 10 ft/s |
| [2.9, 3] | 11.8 ft/s |
| [2.999, 3] | 11.998 ft/s |
The values approach 12 ft/s. That limiting value is the instantaneous velocity at t = 3.
Includes direction. A velocity of −7 m/s means motion at 7 meters per second in the negative direction.
Has no direction and is never negative. For velocity −7 m/s, speed is |−7| = 7 m/s.
Two curve points determine a secant. As the second point moves closer to the first, the secant line rotates toward the tangent line.
05 · Avoid
A rate compares two measurements, so report both units: feet per second, dollars per hour, and so on.
Two separated points give an average rate. The instantaneous rate is the limiting tangent slope.
Position tells where an object is; velocity tells how quickly and in which direction its position is changing.
Velocity may be negative. Speed is its absolute value and cannot be negative.
06 · Check yourself
Decide first, then open the answer.
A secant line. Its slope uses two points on the curve.
A tangent line. Its slope describes the curve at one instant.
12 ft/s. Speed is |velocity|.
6 ft/s. Compute (18−0)/(3−0).
The instantaneous velocity at t = 3 is 12 ft/s. The secant slopes approach that limiting value.
07 · Revisit
Use the corrected transcript to search for a term or return to an explanation. Caption files are available above for offline viewing.
Download corrected transcript