WEBVTT



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Alright, let's start with a little warm-up before we get into actually the new

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material.

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Find the equation of the tangent line at x = 0.

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X equals zero.

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To find the equation of the tangent line, we need its slope.

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To find the slope we need to find the derivative.

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We will use several derivative rules.

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We're not going to use the definition.

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What's the first rule?

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Since we have a sum of a bunch of power functions, we're going to use the...

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No.

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Sum of...

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The sum...

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Did we name it?

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Did I call it something?

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Did I write it down, but we didn't call it something?

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Use the sum and difference rule.

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The derivative of a sum is the sum of the derivatives.

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For each power function, apply the constant multiple rule and the power rule. The

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derivative of 5x cubed starts with 3 times 5, or 15.

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Subtract one from the exponent to get the second power.

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These are easy enough, hopefully we can just do it in our head, we don't have to

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write

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The derivative of 7x is 7, and the derivative of the constant is 0.

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The derivative of a cubic is quadratic; the degree decreases by one because of the

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power rule.

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1 because the power rule and okay here's the derivative at any value x so we want

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Evaluate the derivative at x = 0.

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The slope of the tangent line is 7. Now find its equation.

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The y-value is f(0) = -2.

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Use point-slope form: y minus y-one equals m times x minus x-one.

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The tangent line is y = 7x - 2.

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Okay, so the power rule is very nice, yes?

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It's a lot simpler than,

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we had to use the definition of the derivative

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on that thing and take us a year to do so.

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And of course the sum and difference rule

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and the constant multiple rule.

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Okay, so that was kind of review from Wednesday.

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Today, let's talk about,

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Now find the derivative of sine.

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How are we going to do this?

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Umm, there's rules.

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There's rules?

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I don't know of any rules.

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Negative sign?

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Oh my goodness.

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Now we're going to do it.

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How are we going to find the derivative?

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Thank you.

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Use the definition of the derivative.

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Which is?

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Start with the limit as h approaches zero.

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As h approaches zero.

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Use f(x+h) minus f(x), all over h.

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This becomes sine of x plus h minus sine of x, all over h.

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Okay, now what?

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Distribute sine?

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What do you mean?

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Do something with this?

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What can we do with that?

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Sine of x plus h is not sine x plus sine h.

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Oh. Let's do an example.

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Pi over 2 plus pi over 2.

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What's pi over 2 plus pi over 2?

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Sine of pi.

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Is that sine of pi over 2?

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plus sine of pi over 2. Sine of pi is 0. What is sine of pi over 2? 1. Does 0 equal

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2?

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Definitely not. Okay, we definitely can't do that. Uh oh, we need something else.

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Any other

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What are ideas?

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Can I factor out a sign?

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You get x plus h minus x.

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Definitely can't do that.

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There's no such thing.

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Use a trigonometric identity.

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This is very important.

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Who said that?

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I said that one actually.

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You did?

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Good.

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Okay.

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I don't know, it's not an awesome thing.

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It's awesome.

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Okay, uh, so, we gotta...

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These are some of the trigonometric identities we will use.

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There are infinitely many trigonometric identities; these are the main ones for this

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lesson.

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These are the main ones.

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Which one are we gonna use?

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Use the sine sum identity.

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What'd it go?

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What?

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Uh oh.

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Let's go back here.

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The argument contains a sum, so use the sine addition identity.

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Sum a difference.

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Sum a difference.

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Use sine of alpha plus beta.

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That identity is sine alpha cosine beta plus cosine alpha sine beta.

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the plus and the minus means if it's plus then this is plus if it's minus then it's

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negative so

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Got

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With alpha = x and beta = h, it becomes sine x cosine h plus cosine x sine h.

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sine x cosine h plus cosine x sine h.

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Okay, now what?

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Any ideas?

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What?

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Group the sine x terms and the sine h terms.

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that so first let's rearrange it

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Rearrange the numerator.

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Factor out sine x and cosine x.

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This guy and this guy.

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I like that.

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Now what?

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Um, cosine h minus 1 is identity of something.

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That's it.

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That's cosine square.

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I forgot what these are.

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They have to be cosine squared.

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Oh, that's square.

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They're not.

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They're not.

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We have to be cosine squared minus 1.

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Cosine square.

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Uh, any other ideas?

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this.

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Split the expression into two limits.

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This plus that.

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This becomes the limit of sine x times cosine h minus one, over h, plus the limit of

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cosine x times sine h, over h.

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The first special limit equals zero.

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Sine x is constant with respect to h, so it may be moved outside the limit.

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You don't have to do this, but you could bring it outside the limit.

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The cosine-minus-one limit equals zero.

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The sine-over-h limit equals one.

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The result is sine x times zero plus cosine x times one.

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And there it is!

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The derivative of sine x is cosine x.

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Beautiful.

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That is math has finds.

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Please prove that derivative of sine is cosine.

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So are we gonna do this every single time?

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Definitely not.

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At this point, we just memorize.

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Derivative of sine.

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Okay next one.

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Now find the derivative of cosine.

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Let's work it out people!

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How are we going to start?

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Begin with the limit as h approaches zero of f(x+h) minus f(x), all over h.

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f of x plus h minus f of x all over h.

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Okay. I bet you could do it.

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Finish the proof or finish the limit.

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What's the next step?

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Let's switch these guys.

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Separate the expression into two limits.

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This goes to zero.

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The cosine-minus-one limit is zero and the sine-over-h limit is one, giving cosine x

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times zero minus sine x times one.

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The result is negative sine x.

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Okay, and I think when we went over graphing derivatives we graphed cosine, we

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graphed

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When we graphed the derivative of cosine, it also matched negative sine x.

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We proved it. Beautiful.

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Okay, so we we memorize this one

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at this point

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It's negative sine of x

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The derivative of sine is cosine, and the derivative of cosine is negative sine.

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All right, now we can do any polynomial.

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Any multiple of sine, any multiple of cosine.

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Now consider tangent.

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If we substitute this in, it's going to be a really ugly mess.

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The definition with tangent of x plus h would be a complicated expression.

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Okay, so we're not going to do this

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This right here is going to be real messy

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Rewrite tangent as sine x divided by cosine x.

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Now what

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That's as far as I got.

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I like this.

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The derivative of a sum is the sum of derivatives.

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Is that another rule?

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It's definitely not.

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Okay.

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The derivative of a quotient is not the quotient of the derivatives.

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It's true for sums and differences, not true for quotients.

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Okay. I don't know what I just did here.

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Long story short, we have no idea what the derivative is.

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We will learn the quotient rule after the test.

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We haven't proved that yet, right?

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So that's for next week after the test.

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We cannot finish tangent until we have the quotient rule.

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We're going to do one more.

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No more trig.

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The rest are all quotients.

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We don't have any more quotients.

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Right, uh, cosecant is one over sine, which is another quotient.

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We don't have a quotient rule yet.

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We're going to do e to the x.

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Before we start, what is our number e?

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The number e is approximately 2.71828; it is irrational.

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is the real definition of E? Where did it come from? Natural log is the inverse of E

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to the x. So we first had to find what E to the x was for natural log. Anybody

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remember

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when we first talked about it? I know we did it at Math 2.3 several years ago.

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Where do we use this in math 2.3?

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Compound interest.

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Okay.

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Compound interest uses A = P times the quantity 1 plus r over n, raised to the nt

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power.

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It's a principle, A equals principle.

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Principle times E. Let's do compound interest first.

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The factor is 1 plus r over n, raised to nt.

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Oh boy, people.

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N plus E plus.

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Yeah, that's fine.

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R is your interest rate.

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The variable n is the number of compounding periods per year.

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larger we got the more it just kept getting closer to this one number and

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And then we came up this formula for continuously compounded interest

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E to the RT, right?

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Okay, it has everything to do with this the real definition of E

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The number e is the limit as n approaches infinity.

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X goes to infinity

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Use the quantity 1 plus 1 over n, raised to the nth power.

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which is just that compound

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This is the compound-interest limit with the extra rate and time parameters removed.

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As you go to infinity, this gets very,

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very small, but then the power gets very,

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very big at the same rate.

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We're at the same time,

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It turns out this is exactly the definition of E. This is where the E comes from.

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There is an equivalent definition.

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As h approaches zero, use the quantity 1 plus h, raised to the 1 over h power.

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So, 1 over x.

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These two definitions are equivalent.

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As x goes to infinity, 1 over x goes to 0.

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And as x goes to infinity, this goes to infinity, 1 over x goes to infinity.

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sorry, one over zero goes to infinity.

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Okay, we're gonna use, well, we need this,

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except we're gonna call it this instead.

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So keep this in mind.

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Doesn't matter what the variable is, same exact thing.

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Okay, we'll come back to that.

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Now let f(x) = e to the x.

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The derivative is the limit as h approaches zero.

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Use f(x+h) minus f(x), all over h.

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minus f of x all over h.

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Okay, now what?

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Factor the numerator after using exponent rules.

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That's awesome.

00:26:16.560 --> 00:26:19.200
Okay, I like that except what do we got to do with this first?

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Rewrite e to the x plus h as e to the x times e to the h.

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You have addition in the exponent. We can change this to e to the x times e to the H

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Factor out e to the x.

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I

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Like it now what?

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Replace e using its limit definition.

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Use e as the limit of the quantity 1 plus h, raised to the 1 over h power.

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zero, one plus H to the one over H. What we just talked about.

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Can we have limits inside limits?

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Absolutely.

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be.

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Okay, now what?

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Use the power law for limits to bring the exponent into the inner expression.

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Is a limit of uh, let me just get the law

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I think this was the limit law the limit is whatever x approaches any number

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f of x to the any number n is n to the limit.

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This was one of the limit laws.

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So basically we're going to bring this inside the limit and put it over the

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function.

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Ok, now what?

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For a power raised to a power, multiply the exponents.

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What can we do?

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We can't solve it.

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We can't solve it.

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We can't solve it.

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Rule of exponents any base with an exponent all raised to an exponent. What do we do

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the exponents times them?

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multiply

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The exponent 1 over h times h simplifies to 1.

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Now what?

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The limit of the constant 1 is 1.

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Use the sum and difference laws for limits.

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so we can bring this negative one inside here.

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One plus h minus one simplifies to h.

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Okay.

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Now these ones add to be zero.

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Okay.

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And let me bring this guy out here.

00:31:31.720 --> 00:31:36.920
Factor e to the x outside the remaining limit.

00:31:37.540 --> 00:31:43.840
And this is the limit as h approaches 0.

00:31:49.620 --> 00:31:53.320
The ratio h over h equals 1.

00:31:53.320 --> 00:31:54.220
1.

00:31:54.660 --> 00:31:55.560
1.

00:31:56.340 --> 00:31:57.920
This is 1.

00:31:58.500 --> 00:31:59.760
This is 1.

00:32:00.360 --> 00:32:02.940
We get e to the x times 1.

00:32:05.060 --> 00:32:08.400
Therefore, the derivative of e to the x is e to the x.

00:32:11.860 --> 00:32:14.120
All this for this?

00:32:14.280 --> 00:32:15.880
Yes, it was awesome.

00:32:17.240 --> 00:32:20.360
We just proved the derivative of e to the x is e to the x.

00:32:22.160 --> 00:32:24.380
It's the easiest derivative to find.

00:32:27.560 --> 00:32:32.960
The definition-based proof depends on the limit definition of the number e.

00:32:32.960 --> 00:32:43.340
definition of the number E. Okay and we probably really didn't tell you that

00:32:43.340 --> 00:32:46.924
that's the definition because you didn't know what limits were back a couple years

00:32:46.924 --> 00:32:47.420
ago.

00:32:47.420 --> 00:32:53.200
But now we do. That is the definite. So long story short, we've memorized this

00:32:53.200 --> 00:33:07.940
From now on, memorize that the derivative of e to the x is e to the x.

00:33:07.940 --> 00:33:11.035
Any constant multiple of e to the x differentiates to the same constant multiple of

00:33:11.035 --> 00:33:11.860
e to the x.

00:33:14.260 --> 00:33:15.160
Same seed.

00:33:16.880 --> 00:33:19.960
Now that we have proved the derivative of e to the x, we can use the rule directly.

00:33:21.080 --> 00:33:29.620
We now know derivatives of polynomials, sine, cosine, and e to the x.

00:33:30.620 --> 00:33:33.040
Or the sum of any combination of those.

00:33:34.140 --> 00:33:37.080
Apply the rules to a mixed example.

00:33:55.480 --> 00:33:57.920
This is some crazy function.

00:33:57.920 --> 00:34:18.800
who knows what it looks like so how are we gonna find the derivative here so

00:34:18.800 --> 00:34:24.425
The derivative of a sum is the sum of the derivatives, so differentiate each term

00:34:24.425 --> 00:34:24.800
separately.

00:34:24.800 --> 00:34:37.440
Differentiate each term separately, beginning with the power rule.

00:34:37.440 --> 00:34:51.084
The derivative of 5x to the fourth is 20x cubed. The derivative of 2 sine x is 2

00:34:51.084 --> 00:34:52.600
cosine x.

00:34:53.640 --> 00:34:59.920
The derivative of negative 4 cosine x is positive 4 sine x.

00:35:04.640 --> 00:35:09.900
The derivative of 8e to the x is 8e to the x.

00:35:19.140 --> 00:35:25.720
The derivative is 20x cubed plus 2 cosine x plus 4 sine x plus 8e to the x.

00:35:27.140 --> 00:35:27.660
There it is.

00:35:27.660 --> 00:35:33.320
This gives the slope of the tangent line at any value of x.

00:35:35.660 --> 00:35:37.060
Okay.

00:35:47.240 --> 00:35:47.940
Okay.

00:35:47.940 --> 00:35:48.840
from?

00:35:50.220 --> 00:35:51.620
Okay.

00:36:10.980 --> 00:36:14.700
We know the derivatives of e to the x and sine x, but a product needs another rule.

00:36:15.400 --> 00:36:18.740
Do we know the derivative of a product?

00:36:20.560 --> 00:36:21.840
What's the product rule?

00:36:36.920 --> 00:36:48.700
What's the product rule?

00:36:48.700 --> 00:37:03.940
this is why in the world is it that we got to prove it maybe it's something

00:37:03.940 --> 00:37:12.040
We need the product rule for this expression and the quotient rule for tangent.

00:37:12.040 --> 00:37:20.140
Save those rules for next week after the test.

00:37:20.140 --> 00:37:27.600
The rules from today are enough for the assigned Section 2.2 problems.

00:37:28.140 --> 00:37:28.960
We will stop here.
