WEBVTT



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Okay, so today we're talking about, given a function, how do we graph a derivative?

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This is what we did last class, on Wednesday.

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We're given a function, and we found the derivative.

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And how do we find the derivative?

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by the definition, right, which is the limit as h goes to zero.

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I worked this one out for us and it ends up with this, okay, which is another

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function, okay.

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So this is a quadratic function. The derivative turned out to be a linear function.

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The derivative is the slope of the tangent line.

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We talked about this.

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A slope is a number, not a function.

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So how is this still the slope of the tangent line?

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It depends on the value of x.

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Every single x value, the function has a different slope.

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So you want any slope at any particular point.

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you plug in an x value okay so the derivative is a whole nother function

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This was a quadratic, and the derivative happens to be linear. Given a graph, we

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will attempt to graph its derivative.

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keep giving a graph of some function and we're gonna attempt to graph the

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derivative so here are those two functions the quadratic and then the

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derivatives in red. How are we gonna be given this and come up with this? Why don't

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you

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We always start with the easiest value we know.

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Zero.

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And that's when the slope of the tangent line is zero.

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Right here.

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Anytime you have a minimum or a maximum, when it's a smooth,

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OK, the tangent line is horizontal,

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and the derivative is zero.

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So we're going to start with that.

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And then we find the zeros of the derivative.

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And then you go to the right and the left.

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Soon as we go to the right is it a positive slope or negative slope?

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Positive

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It's just gonna keep getting larger and larger and larger and larger

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So I know this is to the right of whatever number. This is one and a half or

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something

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It's gonna go up

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It's not obvious. It's a straight line

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And for right now it really doesn't matter we know it's positive just keep getting

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larger

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And then we go to the left of that zero or where the slope of the tangent line is

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zero.

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Look, is that a positive slope or negative?

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It's negative, it just keeps getting steeper and steeper.

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And so I know our derivative is a negative number down here, just keep it steeper.

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If we wanted to we could estimate the values of the slope plug them in here and then

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plot

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it but we almost never do that.

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Okay so we just first figure out where the derivative is zero how many times is the

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derivative

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zero?

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So when the has a horizontal tangent line we got one right here one right here and

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one

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There are three horizontal tangents. Wherever we have a horizontal tangent line, the

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derivative is zero.

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zero, the derivative is zero, and the derivative is zero.

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And then between these two zeros of the derivative, just you can put a pencil or you

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can do whatever,

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The tangent line negative or positive

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The slope of the tangent line is negative throughout this interval.

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Here the slope is most negative. Then it is still negative, but becomes less steep

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as it approaches zero.

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so wherever the

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Slope is the steepest

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that's going to be our

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least slope here and

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Just put it some it doesn't matter how down

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If you want to estimate that, I don't know, it's about a slope of negative 2.

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Maybe I should have put it down here at negative 2.

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It doesn't really matter.

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And then we just make a nice smooth curve.

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And then between this 0 and this 0,

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Is the slope of the tangent positive or negative?

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Positive.

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All the way to the next one.

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And somewhere right here is the steepest.

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So I'm going to put some point about here.

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And notice I didn't draw it very high because this is not a very steep value,

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especially

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compared to this.

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And now to the right of that zero the derivative that that local maximum

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Slope is positive negative

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Negative and just keep getting more and more and more and more negative

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So we just

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Put some arrow and then to the left of this

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zero

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So for the tangent line positive,

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The slope of the tangent line is positive, and it keeps getting larger.

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So it just keeps going up and up and up and up and up.

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And that's it.

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That's our best guess as to the graph of the derivative.

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Assuming this original function is a polynomial, what's the least degree this could

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be?

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First how about this?

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Is the degree of this polynomial is an even degree or an odd degree?

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Even on okay now we most of us agree. Why is he even?

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The end behavior

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Both going down to negative infinity.

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Okay. It's some even degree.

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Either x squared, x to the fourth, x to the sixth, x to the eighth.

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So we look at the end behavior. Okay.

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And then we have one, two, three extrema or turning points.

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Where it changes from increasing to decreasing.

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So what does it have to at least be?

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Oh, could it be quadratic?

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No, that's what we know a quadratic look like yeah only has one turning point

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This has three

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Extrema a local min or max so it has to be at least a fourth degrees

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We're good that it could be a sixth degree. We can't tell could be an eighth degree

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but actually at least a fourth degree polynomial.

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And what about the derivative, the Green function?

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Is it an odd degree or even degree?

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Odd.

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It's definitely not linear.

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Could it be cubic?

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It could be cubic.

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It has one, two turning points or two little,

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it could be a cubic, okay?

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And this is always gonna happen with polynomials.

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Whatever the degree of the polynomials,

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the derivative is gonna be one degree less.

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And we'll learn exactly why later.

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So first we figure out where the slope of the tangent line is zero.

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horizontal tangent lines which obviously should be here we put a zero

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we got one and to the right is it negative or positive negative okay it

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just keeps getting more and more and more and more negative and to the left

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positive, steep is getting steeper and steeper.

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It's going to look like this.

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This is a quadratic,

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or could it be a fourth degree problem?

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The derivative of a quadratic is a linear function, so that is why I drew a straight

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line.

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Okay.

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Should have drawn it something like that?

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Yes.

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What type of function is this?

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Definitely not.

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Why not?

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Do polynomials have asymptotes?

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No.

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Okay.

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Polynomials are continuous.

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It's definitely not a polynomial.

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What type of function is this?

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Rational, which is the ratio of two polynomials.

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Are there any parts where the derivative is zero here?

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No.

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So we can't start by doing that.

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So now we just start some other slide.

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Just pick a value.

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This would be the tangent line.

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What's approximately the slope of that line?

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It's about one.

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Right at 45 degree angle has a slope of one.

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Okay.

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So I'm putting it right there at one.

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And then when we go to the right, does it have a positive slope or a negative slope?

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The closer we get to that asymptote, the steeper the slope becomes.

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So in fact that's going to be the derivative.

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and then the farther we go to negative infinity that closer the derivative gets

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The derivative approaches zero farther to the left. It is not the same function as

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the original graph.

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And then right here, what's approximately the slope of that line?

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One, positive one.

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So we need a dot up here at one.

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And then when we go to the right, it's still positive but just keeps getting flatter

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and

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flatter and flatter.

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So positive, but gets very, very, very close to zero.

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And when we go to the left of this x value of two or so, it's positive, but it keeps

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getting steeper and steeper and steeper and steeper and steeper and steeper.

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So this goes up, up, up, up, up, up.

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OK.

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This is also a rational function.

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The derivative of rational functions

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are other rational functions.

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And we'll see why that is later.

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We do the derivative.

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OK, questions on this?

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We go to the right of the zero it's the steepest right, I don't know about here

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Okay right here is the steepest

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So that's gonna be our it's gonna go up to here

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And then the closer we get whatever this is x equals 5 it starts to level off get

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close to zero it's never zero

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And

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And then what's the slope of the tangent line right here at the end point?

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Very important.

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It does not exist.

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Derivatives do not exist at end points.

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Why is that?

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Let's call this number 5.

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The limit as h approaches...

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Let's go to the other definition.

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Approaches 5, f of x minus f of 5, over x minus 5.

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Why does this limit not exist?

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The limit as x approaches five from the left does exist.

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Okay but the limit as x approaches five from the right.

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Okay, this does not exist there are no values to the right of five

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Okay, so that's why the limit as X approaches five does not exist endpoints are not

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differentiable

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Very important so it's same thing on the left here. This is positive gets steeper

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And then we got to put an open circle on the end point

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Problem 42 has one horizontal tangent. To the right, the slope is always negative

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and becomes steeper.

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is always negative and just keeps getting steeper. And again if the function ends,

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there's

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there it's not differentiable somewhere right here is the steepest

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so it's gonna go up and then get closer and closer and closer to zero okay do 43

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Shouldn't get something like that.

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Okay, if you're not understanding where I, or how I do this, please ask.

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And again, where I put the steepest point doesn't really matter.

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I could have drawn it way up here

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We can't really tell because we don't really have numbers to deal with

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Okay, we'll talk about this x point in a second.

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We definitely have a zero here, a zero here, and a zero here.

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When we go to the right of this point, where's the steepest point?

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It just keeps getting steeper and steeper and steeper and steeper and steeper until

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we hit that sharp point.

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So it's just going to get steeper.

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Okay I could have drawn it there or I could have drawn it here.

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It doesn't really matter.

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Just to the right of that sharp point is the slope positive or negative?

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Negative.

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And in fact every single point on that line has the same slope.

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So we are going to draw a negative, some negative value here.

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And it is a horizontal line.

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it's always the same value let's say this is at 7 at x equals 7 that sharp

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point what's the derivative okay definitely does not exist and why is

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that okay it's definitely a cusp but what makes it not differentiable that we

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We need an open circle on each side. Why is the derivative undefined?

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yes this is exactly right the derp the definition is the limit as let's do the

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other definition X approaches 7 of the difference formula or the slope of the

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secant line.

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And the reason it's not differentiable, the limit from the left is going to equal

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whatever

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this number is.

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Let us say the left-hand slope is 8; these are illustrative values.

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Let's make that.

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The limit as X approaches seven from the right

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is gonna be whatever this number is.

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I'm gonna just call it negative two.

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Therefore the limit as X approaches seven.

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It does not exist because the limit from the left and the limit from the right not

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of the function but of the

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We call this the difference quotient

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We call this the difference quotient, or the slope of the secant line.

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Are different so it does not exist. So the reason sharp points are not

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differentiable

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It's by the definition of the derivative the derivative or the limit for the left

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and the right are not the same therefore

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the limit doesn't exist therefore there is no derivative there and it will be

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important to state that later on. Okay question on that problem is that the

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What function is this?

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Is it a cosine?

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Looks just like cosine.

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In fact I believe it is cosine.

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That's right at 2 pi.

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Does it have any horizontal tangent lines?

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Yeah we got lots of them.

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Right here, right here, right here.

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So the derivatives are going to have lots of zeros.

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one here, one here at pi, at 2 pi, 3 pi, negative pi, negative 2 pi.

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Between zero and pi, where is it the steepest?

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Exactly here, at pi over 2.

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In fact, I gave you grid marks. What is the slope of that line?

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Plus one. Negative one.

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It goes down one over one. It's exactly negative one.

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So we go to negative one, which is right here.

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okay and a nice smooth point and then between pi and 2 pi the tangent line the

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The derivative looks a lot like a trig function as well.

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If it were, what would it be?

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It's definitely not sine.

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Sine starts at zero and goes up to one at pi over two.

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But this is the reflection of sine, so it would be negative sine.

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In fact, it turns out, we're going to show this later on, the derivative of cosine

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is

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Exactly negative sine.

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What type of function is this?

00:21:41.370 --> 00:21:42.690
Looks like an exponential function.

00:21:46.230 --> 00:21:48.890
What is the base of the exponential function?

00:21:50.950 --> 00:21:55.010
How do we look at a graph and figure out what the base is?

00:21:56.030 --> 00:21:58.490
X equals 1, what is the value?

00:22:04.150 --> 00:22:08.590
X equals 1, it's right here.

00:22:11.310 --> 00:22:15.950
It's not obvious, but this turns out to be E. What is E?

00:22:16.230 --> 00:22:21.170
This is our function, e to the x.

00:22:29.670 --> 00:22:31.990
It has no minimums or maximums.

00:22:33.210 --> 00:22:35.210
This tangent line will never be zero.

00:22:35.210 --> 00:22:37.430
So we just got to go to some other point.

00:22:39.890 --> 00:22:43.610
Let's pick a point, let's say, right here.

00:22:44.670 --> 00:22:47.450
What is the slope of this line?

00:22:50.770 --> 00:22:52.450
OK, it looks like it's one.

00:22:52.550 --> 00:22:54.110
In fact, it is exactly one.

00:22:55.270 --> 00:22:57.710
I'll put a dot right there at 0 comma 1.

00:23:00.290 --> 00:23:00.810
OK.

00:23:00.810 --> 00:23:04.810
And then to the right here, it's definitely positive.

00:23:06.270 --> 00:23:09.690
And it just keeps getting steeper and steeper and steeper.

00:23:11.350 --> 00:23:22.170
Okay, and this is not exactly obvious here, but that is the derivative to the right.

00:23:23.950 --> 00:23:28.169
And to the left is still positive but keeps getting flatter and flatter and flatter

00:23:28.169 --> 00:23:28.919
and

00:23:29.330 --> 00:23:30.230
flatter.

00:23:33.790 --> 00:23:34.690
Ok.

00:23:36.910 --> 00:23:44.830
And for this function it's not obvious but it turns out the derivative of e to the x

00:23:45.590 --> 00:23:47.750
is exactly the same function.

00:23:47.950 --> 00:23:49.110
It is e to the x.

00:23:49.830 --> 00:23:54.470
Which is kind of crazy and we'll prove that later for you

00:23:59.950 --> 00:24:02.210
Super cool a

00:24:02.210 --> 00:24:06.110
Derivatives of exponential functions are exponential functions as well.

00:24:06.710 --> 00:24:08.930
Sometimes it's exactly the same

00:24:08.930 --> 00:24:13.480
The other times it'll be just a slight coefficient different have a different

00:24:13.480 --> 00:24:15.930
coefficient. It'll still be an exponential function

00:24:16.490 --> 00:24:18.390
Let's assume this goes up forever.

00:24:21.610 --> 00:24:23.330
What type of function is this?

00:24:27.050 --> 00:24:30.230
Or if I gave you an equation for this...

00:24:31.610 --> 00:24:34.330
We have to be some piecewise function.

00:24:35.530 --> 00:24:37.330
OK, that's three different pieces.

00:24:41.910 --> 00:24:45.110
And we'll talk about what the actual function is in a minute.

00:24:47.450 --> 00:24:50.030
It does have a horizontal tangent line right here.

00:24:51.590 --> 00:24:54.590
So the derivative has a 0 right there.

00:24:56.130 --> 00:24:57.410
The derivative is 0 there.

00:24:58.850 --> 00:25:00.250
And then to the right here

00:25:00.990 --> 00:25:03.130
Does have a positive negative slope?

00:25:04.130 --> 00:25:08.668
negative just keeps getting more and more and more negative and then what happens at

00:25:08.668 --> 00:25:09.418
the

00:25:11.610 --> 00:25:17.530
What's the derivative of that sharp point does not exist so

00:25:20.710 --> 00:25:25.330
It's more and more negative we definitely need to put a hole right there

00:25:28.990 --> 00:25:33.510
And instantly to the right, does it have a positive slope or negative slope?

00:25:35.110 --> 00:25:39.067
It's not obvious, but this is getting larger, just barely larger and larger and

00:25:39.067 --> 00:25:39.817
larger.

00:25:40.070 --> 00:25:44.430
So from here, it doesn't exist.

00:25:50.330 --> 00:25:52.410
It looks something like that.

00:25:56.150 --> 00:26:02.470
To the left here, the positive slope, it keeps me steeper and steeper and steeper.

00:26:06.970 --> 00:26:12.350
And then right here, whatever value that is, doesn't exist.

00:26:16.570 --> 00:26:19.570
And then instantly has negative slope

00:26:33.220 --> 00:26:38.100
Derivatives of piecewise functions are also described piecewise.

00:26:41.420 --> 00:26:50.100
In fact, this function, the equation is the absolute value of some quadratic.

00:26:50.360 --> 00:26:52.620
I don't know exactly what quadratic it is.

00:26:52.620 --> 00:26:54.840
I'm just let me make something up.

00:26:55.340 --> 00:26:57.080
x squared minus

00:27:00.300 --> 00:27:01.200
plus

00:27:03.940 --> 00:27:05.940
three x minus

00:27:11.960 --> 00:27:14.220
16 or something like that.

00:27:18.020 --> 00:27:21.600
Anytime you see an absolute value, it's a piecewise function.

00:27:24.180 --> 00:27:26.480
This actually was some quadratic.

00:27:28.440 --> 00:27:34.020
If it was without the absolute value, it'd be exactly this function.

00:27:35.920 --> 00:27:40.500
But because of the absolute value, it flipped this to this.

00:27:41.740 --> 00:27:46.240
It's kind of interesting.

00:27:50.960 --> 00:27:53.980
And again, why is it not differentiable there?

00:27:54.960 --> 00:27:57.520
Let's say this is at 4.2 or something.

00:27:57.520 --> 00:28:02.400
The left- and right-hand limits of the difference quotient are not equal.

00:28:02.670 --> 00:28:04.610
Okay, this is some piecewise function.

00:28:05.470 --> 00:28:09.595
It does have extreme, there's a maximum here and a maximum there and a minimum

00:28:09.595 --> 00:28:10.345
there.

00:28:12.750 --> 00:28:14.330
Is the derivative zero there?

00:28:15.830 --> 00:28:17.070
Definitely not, it's sharp.

00:28:18.070 --> 00:28:20.030
Okay, sharp points are not differentiable.

00:28:20.750 --> 00:28:23.710
The limit from the left of the difference quotient limit from the right are not the

00:28:23.710 --> 00:28:24.550
same.

00:28:24.550 --> 00:28:25.810
So let's just choose some other point.

00:28:26.710 --> 00:28:30.350
Let's say, I don't know, right here.

00:28:31.870 --> 00:28:34.450
What is the slope of that tangent line there?

00:28:37.270 --> 00:28:39.190
It's whatever the slope of that line is.

00:28:39.270 --> 00:28:40.370
What is the slope of that line?

00:28:41.870 --> 00:28:42.770
One.

00:28:43.570 --> 00:28:45.090
Okay, in fact it's right there.

00:28:45.610 --> 00:28:49.070
Everywhere on this point has the same exact slope of the tangent line.

00:28:49.570 --> 00:28:52.670
The slope of a tangent line of a line is always the slope of the line.

00:28:52.670 --> 00:28:57.710
So everywhere here, it's going to have a slope of one

00:28:59.670 --> 00:29:03.550
Sharp points are not differentiable open circle

00:29:08.210 --> 00:29:11.850
So that's this piece here the slope of this line is one

00:29:15.490 --> 00:29:19.410
Between zero and five the slope of that line is negative one

00:29:19.520 --> 00:29:23.660
So it's gonna be like this.

00:29:27.280 --> 00:29:29.100
And one again.

00:29:31.790 --> 00:29:34.950
This is y equals the cube root of x.

00:29:40.910 --> 00:29:44.010
It's the continuous function everywhere.

00:29:45.610 --> 00:29:46.890
Domain's all real numbers.

00:29:53.150 --> 00:29:55.270
It has no minimum or maximum, right?

00:29:56.090 --> 00:29:58.150
So the derivative is going to have no zeros.

00:29:58.610 --> 00:30:03.550
I don't know, somewhere right about here, the slope of the tangent line is one.

00:30:07.450 --> 00:30:08.850
So I'm going to put a dot here.

00:30:09.370 --> 00:30:13.477
Ok, we have a positive slope but it just keeps decreasing and decreasing and

00:30:13.477 --> 00:30:14.227
decreasing.

00:30:15.290 --> 00:30:17.350
So it's going to look something like this.

00:30:19.470 --> 00:30:21.230
And have a horizontal asymptote.

00:30:24.590 --> 00:30:26.290
What happens when I get closer to zero?

00:30:28.230 --> 00:30:30.190
It's steeper and steeper and steeper.

00:30:30.190 --> 00:30:32.530
And right here at zero

00:30:33.830 --> 00:30:36.590
The tangent line is vertical

00:30:38.170 --> 00:30:41.210
What's the slope of vertical lines

00:30:51.030 --> 00:30:53.690
Vertical lines don't have slopes

00:30:54.990 --> 00:30:56.090
Okay like

00:30:57.330 --> 00:31:02.030
x equals 2 is a vertical line. It does not have a slope.

00:31:02.630 --> 00:31:04.730
Vertical lines do not have slopes.

00:31:06.070 --> 00:31:09.210
So right here the derivative does not exist

00:31:09.870 --> 00:31:11.970
because we have a vertical tangent line.

00:31:12.990 --> 00:31:14.410
And the closer you get to 0,

00:31:16.010 --> 00:31:18.510
This has a vertical asymptote, the derivative.

00:31:21.970 --> 00:31:28.370
And then just to the left of zero, it has a positive, very very very steep slope.

00:31:29.270 --> 00:31:31.830
It's going to look something like this.

00:31:31.830 --> 00:31:33.830
It has...

00:31:39.370 --> 00:31:45.455
At this vertical tangent, the derivative does not exist; its graph has a vertical

00:31:45.455 --> 00:31:46.205
asymptote.

00:31:46.710 --> 00:31:47.750
vertical asymptote

00:31:48.450 --> 00:31:51.390
Okay, it might go to positive, it might go to negative, they both...

00:31:51.930 --> 00:31:53.090
which is a semi-circle.

00:32:02.990 --> 00:32:04.930
Let's say this is the semi-circle.

00:32:06.310 --> 00:32:07.310
We definitely have a zero.

00:32:11.190 --> 00:32:12.870
And the slope here is negative.

00:32:14.710 --> 00:32:16.650
We're going to have a vertical asymptote here.

00:32:17.650 --> 00:32:18.610
It's going to look like this.

00:32:19.270 --> 00:32:23.936
Approaching the endpoint, the derivative does not exist at the endpoint, and the

00:32:23.936 --> 00:32:25.730
slopes become steeper and steeper.

00:32:25.730 --> 00:32:26.650
and steeper and steeper.

00:32:26.870 --> 00:32:28.930
It goes all the way to negative infinity.

00:32:30.210 --> 00:32:33.310
And this will go all the way to positive infinity.

00:32:33.850 --> 00:32:38.801
But, okay, yeah, so that makes sure when you draw the graph of a semicircle, the

00:32:38.801 --> 00:32:39.110
closer

00:32:39.110 --> 00:32:41.370
we get to this value, the steeper it gets.

00:32:41.470 --> 00:32:44.230
You're gonna have vertical asymptotes at those two points.
