WEBVTT



00:00:05.900 --> 00:00:21.900
All right. So what's the first thing we always try? Direct substitution. Over here,

00:00:21.900 --> 00:00:35.880
we get 1 over (0 times the square root of 1 plus 0), minus 1 over 0.

00:00:35.880 --> 00:00:45.913
0 go to? Well, in limits, it will either go to positive or negative infinity. It

00:00:45.913 --> 00:00:46.663
depends

00:00:46.540 --> 00:01:06.827
on the left to the right. So let's not worry about the left and right phenomenon. So

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this

00:01:08.020 --> 00:01:11.678
one over zero goes to either positive or negative infinity. This goes to either

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positive or

00:01:12.200 --> 00:01:20.960
negative infinity okay and we get this what is infinity minus infinity not zero

00:01:22.000 --> 00:01:36.340
we don't know what it is it's another indeterminate form okay if these both go

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to positive infinity or sorry let's say the one on the left goes to positive and

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this goes to negative.

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This would be infinity plus infinity,

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which does go to infinity.

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But we don't know,

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because we didn't do it from the left and the right.

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So anytime you get infinity minus infinity,

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indeterminate, we gotta do some more work.

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All right, so this next trick,

00:02:05.460 --> 00:02:08.280
is we just need to combine them into one fraction.

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So we get a fraction minus another fraction.

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We combine them into one fraction.

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So we just need to get a common denominator

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of the two fractions.

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So we just need to multiply this fraction by something. What do we multiply it by?

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So we just need to multiply this guy by something.

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What do we multiply this guy by?

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I have 1 plus x over 1 plus x.

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Now they have a common denominator.

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And now if we try direct substitution, we get 1 minus the square root of 1 plus 0,

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over 0.

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Now we get 0 over 0, which is?

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A different indeterminate form.

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we're gonna do some more work so now what so we go back to one of our other

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tricks multiplied by the conjugate because we got two terms here especially

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one involving square root. So let's multiply by 1 plus 1 plus x. And again, the

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bottom

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or the denominator, which we did not choose the numerator, don't multiply that out.

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Just

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keep that all factored. Yeah. Again the two middle terms of the conjugate add to be

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zero.

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So we get 1 plus 0 minus 1 plus x.

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Now we distribute this guy.

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And now what?

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one of our other tricks.

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cancel the common factor x.

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And now we return to direct substitution and see what happens.

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The denominator becomes 1 times 1 plus 1, so the limit is negative one-half.

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Okay, so.

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So the very first trick was to combine multiple fractions or the sum or

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difference of fractions into one fraction.

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And then also the other trick is keep trying more tricks.

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Another technique.

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Alright.

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Alright.

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Direct substitution: what is sine of zero?

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Oh what do we do here okay this next

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trick very important one you just memorize the answer memorize okay this

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is one of the ones we're just gonna memorize the answer is one here it's not

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obvious

00:06:42.480 --> 00:06:45.760
Ok, so here is our function sine of x and x.

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As you approach zero, these two functions get closer and closer and closer to each

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other.

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And when you divide two numbers that are very, very close,

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it gets closer and closer to 1.

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If I zoom in here, the closer you get to 0, the closer

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you can tell the difference between the two.

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And then if I show you this function, y equals sine x.

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It's the green function.

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There is a hole right there at x equals zero.

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That function doesn't exist at x equals zero.

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However, you approach from the left and the right, it gets closer and closer to one.

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So the trick is you just memorize this one.

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Okay.

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Okay. One of the limits we memorize is this one: sine of x over x.

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Sine of x over x.

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O-Rex...

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What about this?

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Is this also going to equal one or no?

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It's going to be negative.

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That's right.

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It's just a guess. That's not a bad guess.

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Not quite true, but it's not a bad guess.

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Is this going to equal one? Why or why not?

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Is this true?

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wrote down here yes okay right if you had this you take the numerator it's one

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multiplied by the reciprocal and you get exactly that okay so this limit is the

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limit as x approaches zero of one divided by sine of x over x. And one of the limit

00:09:08.800 --> 00:09:21.112
laws that I handed out is the limit of a quotient is the quotient of limits. So we

00:09:21.112 --> 00:09:22.480
could write

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this as the limit as X approaches 0 of 1 divided by the limit as X approaches 0

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sine of X over X and what is this limit? Limit of a constant is just that constant

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And this limit we just memorized is 1 is definitely equal to 1.

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Long story short, limit as x approaches 0 of sine of x over x or x over sine of x is

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1.

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Very important.

00:10:14.080 --> 00:10:15.780
So if we try direct substitution,

00:10:15.960 --> 00:10:20.280
we get 1 minus cosine of 0 over 0.

00:10:21.860 --> 00:10:23.420
What is cosine of 0?

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0 over 0.

00:10:37.420 --> 00:10:39.300
So, is this also going to equal one?

00:10:45.600 --> 00:10:47.560
It's going to be one?

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Some people shake their head no?

00:10:52.520 --> 00:10:56.940
We are also going to memorize this one, but let's figure it out before we get the

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answer.

00:11:01.100 --> 00:11:02.800
Here's a little trick.

00:11:04.800 --> 00:11:09.400
We're going to multiply by 1 plus cosine of x.

00:11:12.540 --> 00:11:18.160
which is just a conjugate of the numerator there.

00:11:21.520 --> 00:11:28.200
These add to be zero.

00:11:31.080 --> 00:11:32.880
Does that help anything?

00:11:34.500 --> 00:11:37.320
You direct substitution, you still get 0 over 0.

00:11:39.380 --> 00:11:46.160
However, I could substitute this for something.

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What is 1 minus cosine squared always equal to?

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Sine squared, right?

00:11:50.480 --> 00:11:55.000
Because sine squared plus cosine squared equals 1.

00:11:58.100 --> 00:12:01.000
So sine squared is one minus cosine squared.

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If you try direct substitution, we still get zero over zero.

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Any ideas what we could do from here?

00:12:26.640 --> 00:12:27.600
What's that?

00:12:37.740 --> 00:12:39.780
I'm not sure we could do that.

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However, sine squared is sine times sine, correct?

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We have an x down here, so we're going to rewrite this as this.

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sine of x over x times sine of x over 1 plus cosine of x.

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And what is the limit of this guy, guys?

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So the limit of a product is the product of limits.

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So I'm going to rewrite like this.

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this

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limit is equal to 1 and now we directly substitute and we get sine of 0 which is

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0 1 plus cosine of 0 which is 1 which is 0 over 1 plus 1 which the whole thing is

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simply zero. Okay, and what we typically do, or what I typically do, instead of

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writing

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the limit of the quotient, a limit times a limit, this is technically what's

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happening.

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what we typically do is just we say this thing goes to 1 and the limit x goes to 0

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of

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sine of x over 1 plus cosine of x and then we get 0 over 1 or 2 so if you ever

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see me like put arrows here that's just meaning whatever this function is it

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goes to whatever the limit of it goes to that number just kind of saves you time

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from writing the limit times limits on okay so this is another one we memorize

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this is really the only other one we memorize

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This is just slightly different.

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How is this different than 3 to the 1?

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The last one was 1 minus cosine of x, this is cosine of x minus 1.

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Is this also going to be equal to 0?

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Take a guess yes or no everybody give me a thumb.

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Okay let's work it out it does equal to one I'm sorry does equal to zero.

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If I factor out a negative out of that, I get the limit as x goes to zero.

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And then one of our limit laws if we have a coefficient in front what can I do with

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that?

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You could distribute what are my limit laws here?

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Or wasn't at the very top yeah, here it is

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This one right here.

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You have a coefficient in front, what can I do with the coefficient?

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We can bring it outside the limit right here.

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So this can come out.

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we get negative 1 times this limit and then let me rewrite these two

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negative cosine plus x plus 1 is 1 minus cosine of x

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and what's this equal to

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Zero, one of the ones we memorized.

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We just did, so it's negative one times zero, it is zero.

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You don't really have to memorize it, but again, the reciprocal of this is the same

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value and if these are swapped it's the same value. They're both 0, they're both 1

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Let me just write that down anyways.

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x over sin x

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also equals to

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one minute

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So the reciprocal has the same value here.

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And we can swap that.

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I'm going to do some algebra.

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All right, next one.

00:18:43.800 --> 00:18:47.220
I'll try direct substitution.

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We get 0 times secant of 0 times cosecant of 0.

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What is secant of zero?

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What is cosine of zero?

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Which is one.

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And cosecant of x?

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What is sine of zero?

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Zero. So one of this does not exist.

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So, we got to do something else.

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What are we going to do?

00:19:31.360 --> 00:19:32.260
Any ideas?

00:19:36.320 --> 00:19:40.100
Figuring out secant, cosecant, cotangent, they are hard, right?

00:19:40.460 --> 00:19:42.560
Because then it is just the reciprocal sign goes in.

00:19:42.820 --> 00:19:45.400
So the trick is just change everything in terms of sine and cosine.

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So all trig functions can be changed in terms of sine and cosine. So this is the

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limit as x goes to 0, x times 1 over cosine of x times 1 over sine of x.

00:20:11.000 --> 00:20:12.860
Now what?

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What does this guy go to as x goes to zero?

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One.

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One.

00:20:21.420 --> 00:20:23.700
So if you want to split it up we can.

00:20:28.380 --> 00:20:36.653
The limit as x goes to zero of one over cosine times the limit as x goes to zero of

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x over

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sine of x.

00:20:41.380 --> 00:20:44.160
And then this direct substitution, we get 1.

00:20:46.020 --> 00:20:50.200
And this, we memorized as 1, the answer is 1.

00:20:54.580 --> 00:20:57.340
So the trick is just change all trig functions

00:20:57.340 --> 00:20:58.760
in terms of sine and cosine.

00:21:01.700 --> 00:21:09.440
So here it's not sine of x over x, sine of x over 7x.

00:21:11.400 --> 00:21:13.020
So what can we do with that?

00:21:17.820 --> 00:21:19.420
Yeah, all we do is we factor this is,

00:21:20.960 --> 00:21:23.540
it's just a coefficient of like 1 7th.

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And we factor it out.

00:21:38.700 --> 00:21:41.840
We have 1 7 times 1 is 1 7.

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That one shouldn't have been too hard, but let's try this one.

00:22:01.900 --> 00:22:04.840
Can I factor out a 5 here?

00:22:08.600 --> 00:22:09.500
Definitely not.

00:22:10.660 --> 00:22:12.780
You can't factor a number out from inside a trigonometric function.

00:22:14.220 --> 00:22:15.220
Uh oh, so now what?

00:22:17.900 --> 00:22:19.640
Multiply by 5 over 5.

00:22:20.560 --> 00:22:22.300
Okay, I like that.

00:22:24.560 --> 00:22:27.420
Multiply this by 5 over 5.

00:22:29.380 --> 00:22:33.580
And take this guy out

00:22:47.380 --> 00:22:49.240
Why did you want that

00:22:53.920 --> 00:22:54.820
It functions.

00:22:56.640 --> 00:23:00.300
Yeah, so even though it's not sine of x over x,

00:23:01.540 --> 00:23:05.180
it's the same exact thing.

00:23:06.900 --> 00:23:11.460
And as x goes to 0, 5x also goes to 0.

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And this goes to 0 at exactly the same rate.

00:23:17.120 --> 00:23:28.960
If you wanted to, you could let like, uh, u, uh, yeah, let me go, u is five X.

00:23:32.920 --> 00:23:38.400
And the limit as X goes to zero of u.

00:23:40.300 --> 00:23:41.200
Okay.

00:23:40.940 --> 00:23:44.440
This also goes to zero and you end up with something like this.

00:23:44.440 --> 00:23:52.140
you don't really have to do this, but sine of u over u.

00:23:52.900 --> 00:23:57.280
And this limit, whatever the variable is, is equal to 1.

00:24:03.420 --> 00:24:07.980
So the key here, as long as whatever is inside the sine

00:24:08.560 --> 00:24:11.800
has to be that same thing down here.

00:24:13.540 --> 00:24:16.960
This will equal to, well, in this case, 5.

00:24:18.180 --> 00:24:24.380
This will equal, in this case, 5.

00:24:24.380 --> 00:24:25.300
bring the letters out.

00:24:29.140 --> 00:24:33.720
Oh, here's a good one.

00:24:34.000 --> 00:24:34.900
All right.

00:24:34.380 --> 00:24:35.280
New topic.

00:24:35.140 --> 00:24:36.040
Yeah.

00:24:38.520 --> 00:24:46.640
We try direct substitution, we get 3 minus 3, or 3 minus 3, we get 0 over 0.

00:24:48.080 --> 00:24:49.980
What in the world are we going to do here?

00:24:58.640 --> 00:25:06.580
Uh, this absolute value, what kind of function is that?

00:25:08.460 --> 00:25:15.398
What's that? It's a piecewise function. Okay, let's look at the definition of the

00:25:15.398 --> 00:25:17.380
absolute value of x

00:25:17.380 --> 00:25:18.792
minus three. This is a piecewise function. It's either going to be x minus three or

00:25:18.792 --> 00:25:19.542
it's

00:25:18.880 --> 00:25:26.000
x minus three if x minus three is greater than or equal to zero and if x

00:25:26.000 --> 00:25:41.700
minus three is less than zero so x minus three it's either x minus three if x is

00:25:41.700 --> 00:25:43.500
Yeah, greater than or equal to zero.

00:25:44.620 --> 00:25:46.680
Sorry, greater than or equal to three.

00:25:49.320 --> 00:25:51.060
Negative x plus three.

00:25:54.340 --> 00:25:56.780
Let me just leave this x minus three.

00:26:00.240 --> 00:26:01.800
If x is less than three.

00:26:03.360 --> 00:26:05.040
Okay, all absolute value functions

00:26:05.040 --> 00:26:06.520
are piecewise functions, right?

00:26:06.740 --> 00:26:07.800
They all, they look like a V.

00:26:08.580 --> 00:26:09.900
There's two different pieces.

00:26:15.000 --> 00:26:21.080
Okay, so going back here, we're going to have to write a piecewise definition.

00:26:27.620 --> 00:26:29.940
So we're approaching three here, right?

00:26:30.060 --> 00:26:31.700
Not from left to right, but both sides.

00:26:33.500 --> 00:26:36.480
But this thing depends on each side of the three.

00:26:36.480 --> 00:26:42.311
So we're gonna have to break these up into the left-hand limit and the right-hand

00:26:42.311 --> 00:26:43.061
limit.

00:26:43.160 --> 00:26:54.440
So the limit as x approaches 3.

00:26:54.900 --> 00:26:55.860
Start from the left.

00:27:06.860 --> 00:27:14.193
OK, so since we're going from the left, are we always greater than or equal to 3 or

00:27:14.193 --> 00:27:14.943
less

00:27:14.600 --> 00:27:15.500
than 3?

00:27:16.600 --> 00:27:18.380
Less than 3.

00:27:19.280 --> 00:27:22.360
So I'm going to substitute this for this right here.

00:27:23.500 --> 00:27:29.500
So this is the limit as x approaches 3 from the left

00:27:30.920 --> 00:27:37.720
of negative, open parenthesis, x minus 3, close parenthesis, over 3 minus x.

00:27:44.460 --> 00:27:48.660
Which is the limit as x approaches 3 from the left.

00:27:48.660 --> 00:27:59.124
I distribute that negative and switch it, we get 3 minus x over 3 minus x, which

00:27:59.124 --> 00:27:59.874
simplifies

00:27:59.740 --> 00:28:01.880
to 1.

00:28:04.560 --> 00:28:11.980
And now let's take the limit as x approaches 3 but from the right-hand side.

00:28:15.040 --> 00:28:21.120
Now, since we're approaching three from the right, this absolute value.

00:28:26.460 --> 00:28:31.220
Okay, we're to the right of three, so I can substitute this in.

00:28:33.860 --> 00:28:38.720
So this is x minus three over three minus x.

00:28:41.280 --> 00:28:42.320
And...

00:28:46.940 --> 00:28:49.020
How do I simplify this?

00:28:53.100 --> 00:28:54.060
You can factor out the negative.

00:28:57.920 --> 00:29:09.780
Either from the numerator or denominator, we get negative x plus three, which if you

00:29:09.780 --> 00:29:19.640
around they simplify to 1 and now we get negative so the limit from the left

00:29:19.640 --> 00:29:26.480
exists it's equal to 1 the limit from the right exists negative 1 so what is

00:29:26.480 --> 00:29:35.840
the limit as X approaches 3 this does not exist

00:29:46.220 --> 00:29:51.886
Just to get an idea of this function right here, I think it looks something like

00:29:51.886 --> 00:29:52.636
this.

00:29:54.300 --> 00:29:57.280
everywhere to the right.

00:30:00.760 --> 00:30:02.440
It's got a cool function.

00:30:04.500 --> 00:30:09.161
We're to the right of 3, it's always going to be negative 1, or left to be positive

00:30:09.161 --> 00:30:09.911
1.

00:30:10.640 --> 00:30:11.740
Okay, so what's this trick?

00:30:12.640 --> 00:30:16.020
Is we have to break up piecewise functions into two pieces.

00:30:18.200 --> 00:30:20.540
And especially involving absolute value.

00:30:20.540 --> 00:30:24.320
Okay, so break up.

00:30:27.060 --> 00:30:44.387
Okay, especially involving anything involving absolute values is a piecewise

00:30:44.387 --> 00:30:46.120
function.

00:30:48.740 --> 00:30:49.960
All right, what are we going to do here?

00:30:53.720 --> 00:30:58.660
Actually, let's do a, no, let's just do this one.

00:31:02.300 --> 00:31:05.180
Here we cannot just use direct substitution.

00:31:07.220 --> 00:31:13.660
If I use direct substitution, you plug in 1 to the function.

00:31:13.820 --> 00:31:14.860
What is f of 1?

00:31:18.640 --> 00:31:21.720
Do I plug it into here or do I plug it into here?

00:31:23.100 --> 00:31:26.160
The top one, because that's in this domain right here.

00:31:27.100 --> 00:31:32.080
So that's ln of 1, which is equal to 0.

00:31:34.220 --> 00:31:40.399
We can't use direct substitution because, well we can only if we know it's

00:31:40.399 --> 00:31:41.149
continuous.

00:31:41.780 --> 00:31:45.457
And we don't know if this function is continuous because this has two different

00:31:45.457 --> 00:31:46.207
pieces

00:31:46.480 --> 00:31:52.580
Okay, so especially any time it changes right here at whatever number this is

00:31:52.580 --> 00:31:56.755
We got to just break up and do the left-hand limit and the right-hand limit. So

00:31:56.755 --> 00:31:58.060
let's start with the left

00:31:59.120 --> 00:32:00.080
X approaches

00:32:01.240 --> 00:32:03.080
0 sorry 1

00:32:04.480 --> 00:32:05.720
From the left

00:32:18.980 --> 00:32:24.260
Now, since we're always to the left, what is f of x?

00:32:27.100 --> 00:32:28.160
Is x squared.

00:32:28.440 --> 00:32:33.620
So I can write the limit as x approaches 1 from the left of x squared.

00:32:36.220 --> 00:32:38.480
Now this is a continuous function.

00:32:38.480 --> 00:32:41.160
So we can just use direct substitution.

00:32:42.280 --> 00:32:44.860
If we plug it in, we get 1 squared, which is 1.

00:32:50.960 --> 00:32:56.660
As we approach from the

00:32:56.660 --> 00:33:01.260
right of f of x

00:33:10.280 --> 00:33:17.000
Okay, since we're always to the right of one, our function is equal to ln of x.

00:33:18.520 --> 00:33:22.040
So I can substitute in for f of x ln of x.

00:33:25.200 --> 00:33:28.880
And again, this is a continuous function, so we can just plug it in.

00:33:33.180 --> 00:33:40.340
And we get ln of 1 and ln of 1 is 0.

00:33:44.300 --> 00:33:47.480
So the left-hand limit exists, the right-hand limit exists.

00:33:49.720 --> 00:33:52.660
So what is this limit as x approaches 1?

00:33:53.800 --> 00:34:01.040
It does not exist because the left-hand limit does not equal the right-hand limit.

00:34:07.580 --> 00:34:17.620
A more interesting question is: what if the lower piece were x squared plus c?

00:34:17.620 --> 00:34:29.060
The question is, what value of C makes this continuous everywhere?

00:34:29.060 --> 00:34:29.960
everywhere.

00:34:32.340 --> 00:34:33.860
So you look at each piece.

00:34:34.200 --> 00:34:35.400
Is this continuous everywhere?

00:34:38.320 --> 00:34:39.220
Not really.

00:34:40.140 --> 00:34:41.820
It is continuous on what domain?

00:34:42.260 --> 00:34:43.440
Why won't it change colors?

00:34:44.820 --> 00:34:47.440
As long as x is greater than zero, it's continuous.

00:34:48.160 --> 00:34:50.860
And it's only this when it's continuous, or sorry,

00:34:51.220 --> 00:34:52.120
when it's that function.

00:34:52.320 --> 00:34:54.300
So this is continuous everywhere here.

00:34:55.660 --> 00:34:58.200
This is, no matter what c is, is a polynomial.

00:34:59.120 --> 00:35:00.860
So it's definitely continuous everywhere here.

00:35:01.060 --> 00:35:05.940
So the only question is, at 1, we got to make it continuous.

00:35:07.560 --> 00:35:16.040
So we got to, this is.

00:35:21.520 --> 00:35:22.900
This is natural log.

00:35:24.220 --> 00:35:29.160
And then this is just x squared.

00:35:33.220 --> 00:35:37.280
So we just have to shift it up or down so at one they're exactly the same value.

00:35:40.560 --> 00:35:44.860
Long story short, we just need to have the two limits equal.

00:35:47.360 --> 00:35:55.260
With plus c, the left-hand limit would be 1 plus c.

00:35:57.060 --> 00:35:58.700
So to make it continuous, we just

00:35:58.700 --> 00:36:00.780
have to make sure these match.

00:36:02.100 --> 00:36:04.040
So 1 plus C equals 0.

00:36:04.720 --> 00:36:05.840
C is negative 1.

00:36:09.720 --> 00:36:11.940
OK, that was, we're going to get to more

00:36:11.940 --> 00:36:13.180
about continuous functions later,

00:36:13.180 --> 00:36:18.620
but just a little quick question. Let's see.
